(y+2)^2/3-4(y+2)^1/3=21

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Solution for (y+2)^2/3-4(y+2)^1/3=21 equation: 


y in (-oo:+oo)

((y+2)^2)/3-((4*(y+2)^1)/3) = 21 // - 21

((y+2)^2)/3-((4*(y+2)^1)/3)-21 = 0

((y+2)^2)/3+(-4/3)*(y+2)-21 = 0

((y+2)^2)/3-4/3*(y+2)-21 = 0

((y+2)^2)/3+(-4/3*3*(y+2))/3+(-21*3)/3 = 0

(y+2)^2-4/3*3*(y+2)-21*3 = 0

y^2-63-4 = 0

y^2-67 = 0

(y^2-67)/3 = 0

(y^2-67)/3 = 0 // * 3

y^2-67 = 0

1*y^2 = 67 // : 1

y^2 = 67

y^2 = 67 // ^ 1/2

abs(y) = 67^(1/2)

y = 67^(1/2) or y = -67^(1/2)

y in { 67^(1/2), -67^(1/2) }

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